求∫根号下(a눀-x눀)⼀x的四次方

2025-06-23 02:37:03
推荐回答(3个)
回答1:

简单计算一下,答案如图所示

回答2:

回答3:

let

x=asinu
dx=acosu du

∫√(a^2-x^2)/x^4 dx
=∫ [(acosu)/(asinu)^4] .[acosu du]
=(1/a^2) ∫ (cosu)^2/(sinu)^4 du
=(1/a^2) ∫ (cotu)^2. (cscu)^2 du
=-(1/a^2) ∫ (cotu)^2. dcotu
=-[1/(3a^2)] (cotu)^3 + C
=-[1/(3a^2)] [√(a^2-x^2)/x ]^3 + C