设公差为d,由a1=1,a7=4,得d= a7?a1 7?1 = 4?1 6 = 1 2 ,所以an=1+ 1 2 (n?1)= 1 2 (n+1),设公比为q,则q= b3 b2 = 2 3 2 = 1 3 ,所以bn=b2qn?2= 2 3n?2 ,由bn< 1 a80 得, 2 3n?2 < 1 81 2 ,即3n-2>81,解得n>6,所以满足bn< 1 a80 的最小自然数n为7,故选C.