答案是什么啊?(x-y)(x2+y2)? x3-y3-xy(x-y)=(x-y)(x2+xy+y2)-xy(x-y)=(x-y)(x2+y2)
(x-y)(x2+y2)2是平方
X^2(x-y)+y^2(x-y)=(x-y)(x^2+y^2)
x³-y³-x²y+xy² =(x-y)(x²+xy+y²)-xy(x-y) =(x-y)(x²+xy+y²-xy)=(x-y)(x²+y²)
x³-x²y+xy²-y³=x²(x-y)+y²(x-y)=(x-y)(x²+y²)