已知向量a,b夹角为45°,且|a|=1,|2a-b|=√10,则|b|=?

2025-06-22 05:27:59
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回答1:

|2a-b| = 根号10 =》 (2a-b)*(2a-b) = 10 => 4a^2 + |b|^2 - 4|a||b|cos(a,b) = 10
=>|b|^2-2√2|b| - 6 = 0=>|b| = 3√2(负根略)