1.先化简,再求值:x⼀x+2-x눀+2x+1⼀x+2 ÷ x눀-1⼀x-1,其中x=√3-2

2025-06-22 10:46:32
推荐回答(1个)
回答1:

x/x+2-x²+2x+1/x+2 ÷ x²-1/x-1
=x/(x+2)-(x+1)²/(x+2) ÷(x+1)(x-1)/(x-1)
=x/(x+2)-(x+1)²/(x+2) ×1/(x+1)
=x/(x+2)-(x+1)/(x+2)
=(x-x-1)/(x+2)
=﹣1/(x+2)
将x=√3-2代入
原式=﹣1/(x+2)
=﹣1/√3-2+2
=﹣√3/3