求(tan10°-根号3)*cos10°⼀sin50°的值

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2025-06-21 22:24:39
推荐回答(1个)
回答1:

(tan10°-√3)*cos10°/sin50°
=(sin10°-√3cos10°)/sin50°
=2(1/2*sin10°-√3/2*cos10°)/sin50°
=2(sin10°cos60°cos10°sin60°)/sin50°
=2sin(10-60)°/sin50°
=2sin(-50)°/sin50°
=-2sin50°/sin50°
=-2