cos4α+4cos2α+3=8(cosα)^4怎么证明

2025-06-21 18:37:49
推荐回答(1个)
回答1:

cos4α+4cos2α+3
=2cos^2(2a)-1 +4(2cos^2a-1)+3
=2(2cos^2a-1)^2-1+8cos^2a-4+3
=2(4cos^4a-4cos^2a+1)-1+8cos^2a-1
=8cos^4a-8cos^2a+2-1+8cos62a-1
=8cos^4a
就是你写的8(cosa)^4