数学函数的连续性

2025-06-22 08:19:54
推荐回答(1个)
回答1:

f(-1-)=1+lim(x->-1-)(x+1)sin(1/x+1)=1
f(-1+)=f(-1)=1
f(0)=1
f(0+)=lim(x->0+)arctanx=0
-1连续,0不连续