求下这个积分∫1⼀(1-v눀/a눀)dv

2025-06-22 23:04:14
推荐回答(1个)
回答1:

∫ 1/(1 - v²/a²) dv
= a∫ a/(a² - v²) dv
= (a/2)∫ [(a - v) + (a + v)]/(a² - v²) dv
= (a/2)∫ [1/(a + v) + 1/(a - v)] dv
= (a/2)[ln|a + v| - ln|a - v|] + C
= (a/2)ln| (a + v)/(a - v) | + C