木块受到的浮力为F浮=ρ水gV排=103kg/m3×10N/kg×75×10-6m3=0.75N;∵木块漂浮,∴G=F浮=0.75N,木块的质量:m= G g = 0.75N 10N/kg =7.5×10-2 kg.答:(1)木块受到的浮力为0.75N; (2)木块的质量是7.5×10-2 kg.